Subtract the sum of 3a(a-b +c) and 2b(a + b - c) from 7c(-a +b+c)
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Step-by-step explanation:
3a^2-3ab+3ac+2ab+2b^2-2bc=3a^2-ab+3ac+2b^2-2bc
[7c(-a+b+c)=-7ac+7bc+7c^2]
now to subtract
-7ac+7bc+7c^2-(3a^2-ab+3ac+2b^2-2bc)
-7ac+7bc+7c^2-3a^2+ab-3ac-2b^2+2bc
-10ac+9bc+7c^2-2b^2+ab
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