Subtract the sum of 3a²-2a+5 and a²-5a-7 from the sum of 5a²-9a+3 and 2a-a²-1
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Answered by
11
Answer:
3a²-2a+5 + a²-5a-7
=>4a²-7a-2
5a²-9a+3 + 2a-a²-1
=>4a²-7a+2
so, now
4a²-7a+2-4a²+7a+2
=4
Answered by
9
Answer:
4
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