Question

Subtract the sum of 3a² -2a +5 and a²-5a-7 from the sum of 5a²- 9a+3 and 2a-a² -1.
​

Answer 1

Answer:

= 2a² - 4a + 4

Step-by-step explanation:

First We Will Do Addition of equations One by one

= (3a² -2a +5) + (a² - 5a - 7)

Taking like Terms Aside

= (3a² + a²) + (-2a - 5a) + (5 - 7)

= (4a²) + (-7a) + (-2)

= 4a² -7a - 2

Now Second,

= (5a²- 9a + 3)  + (2a - a² - 1 )

Taking Terms In Descending order of powers

= (5a² - 9a + 3) + (a² - 2a -1)

Taking like Terms Aside

= (5a² + a²) + (-9a -2a) + (3 - 1)

= (6a²) + (-11a) + (2)

= 6a² - 11a +2

Now Subtracting,

= (6a² - 11a +2) - (4a² -7a - 2)

= (6a² - 4a²) + (-11a + 7a) + ( 2 + 2)

= 2a² - 4a + 4

please mark me as brainliest