Math, asked by khushbooansari922, 6 hours ago

Subtract the sum of 3a7-8ab-4b²+1 and 6-10ab-56²1 from the sum of 2b²+7ab-5a²-9 and a²+²-7ab +3​

Answers

Answered by yuktasingh7581
2

Answer:

We have to Subtract 5a² - 7ab + 5b² from 3ab - 2a² - 2b²

So A/Q we have

3ab-2a² - 2b² - (5a² - 7ab + 5b²)

= 3ab2a² - 2b² - 5a² + 7ab - 5b²

= 10ab-7a²-7b²

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