subtract the sum of 3p-2q+5p+3q-2r and -4p+2q-3r from the sum of 2p-3q-3r,4p-q-r and 3p+2q-3r
Answers
Answered by
1
(9p-2q-7r) - (4p+3q-5r) = 5p-5q-2r
Answered by
5
[(2p-3q-3r)+(4p-q-r)+(3p+2q-3r)]-[(3p-2q+5p+3q-2r)+(-4p)+2q-3r)]
=(2p+4p+3p-3q-q+2q-3r-r-3r)-(3p+5p-4p-2q+3q+2q-2r-3r)
=(9p-2q-7r)-(4p+3q-5r)
=9p-2q-7r-4p-3q+5r
=6p-5q-2r
=(2p+4p+3p-3q-q+2q-3r-r-3r)-(3p+5p-4p-2q+3q+2q-2r-3r)
=(9p-2q-7r)-(4p+3q-5r)
=9p-2q-7r-4p-3q+5r
=6p-5q-2r
Ashirbadnaik:
thankssss
Similar questions