Question

. Subtract the sum of 3x ^ 2 - 5x and x ^ 2 + 2x + 5 from the sum of 4 + 3x and 5 - 4x + 2x ^ 2​

Answer 1

Answer:

$\huge \underline \mathfrak\color{red}{Answer↓}$

$\huge{\fcolorbox{Red}{Green}{-2x²+2x+4}}$

Step-by-step explanation:

$(4 + 3x + 5 - 4x + 2 {x}^{2} )- (3 {x}^{2} - 5x + {x}^{2} + 2x + 5)$

$= (3x - 4x + 4 + 5 + 2 {x}^{2} ) - (3 {x}^{2} + {x}^{2} - 5x + 2x + 5)$

$= ( - x + 9 + 2 {x}^{2} ) - ({4x}^{2} - 3x + 5)$

Remove the parenthesis

$= - x + 9 + 2 {x}^{2} - 4 {x}^{2} + 3x - 5$

$= 2 {x}^{2} - 4 {x}^{2} - x + 3x + 9 - 5$

$= - 2 {x}^{2} + 2x + 4$