Question

subtract the sum of (3x+2) and (3x-2) from the sum of (4x+ 5) and (5x-2)

Answer 1

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First we have to add 3x2 − 5x + 2 and − 5x2 − 8x + 9 then from the result we have to subtract 4x2 − 7x + 9.

= {(3x²–5x+2) + (-5x²–8x+9)} – (4x²–7x+9)

= {3x²–5x+2–5x²–8x+9} – (4x²–7x+9)

= {3x²–5x² – 5x–8x+2+9} – (4x²–7x+9

= {- 2x²–13x+11} – (4x²–7x+9)

= – 2x²–13x+11–4x²+7x–9

= – 2x²–4x²–13x+7x+11–9

= – 6x²–6x+2

Answer 2

Answer;

answer is 11x2-17x-6

Step-by-step explanation:

add(3x+2) and (3x+2)= (9x2-4)

add(4x+5) and (5x-2)= (20x2-17x-10)

(20x2-17x-10)- (9x2-4)=========11x2-17x-6.................