Question

Subtract the sum of 3x2 + 2xy - 22 and 5y2 - 7xy from 5x2 + 2y2 – 3xy​

Answer 1

Answer:

Sum of 3x2+2xy−2y2 and 5y2−7xy

=3x2+2xy−2y2+5y2−7xy

=3x2−5xy+3y2

Now 

5x2+2y2−3xy

3x2+3y2−5xy

−   −      +

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2x2−y2+2xy

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=2x2+2xy−y

Step-by-step explanation:

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Answer 2

Answer:

2x² - 3y²+ 2xy + 22

Step-by-step explanation:

Sum of (3x² + 2xy - 22) and (5y² - 7xy)

3x² + 2xy - 22 + 5y² - 7xy

3x² + 5y² - 5xy - 22

(5x² + 2y² - 3xy​) - (3x² + 5y² - 5xy - 22)

5x² + 2y² - 3xy - 3x² - 5y² + 5xy + 22

2x² - 3y²+ 2xy + 22