Math, asked by vanshikatomar4550, 7 months ago

.Subtract the sum of 3x²+5xy+7y²+3 and 2x²-4xy-3y²+7 from 9x²-8xy+11y².​

Answers

Answered by Rishith1902
5

Answer:

answer is 3x² - 10xy - 10y² - 9  

Step-by-step explanation:

sum of 4x² + 7xy + 3y² + 1 and 2x² - 5xy - 2y² + 8

4x² + 7xy + 3y² + 1 + 2x² - 5xy - 2y² + 8

6x² + 2xy + y² + 9

subtract of 6x² + 2xy + y² + 9 from 9x² - 8xy + 11y²

9x² - 8xy + 11y² - (6x² + 2xy + y² + 9)

9x² - 8xy + 11y² - 6x² - 2xy - y² - 9

3x² - 10xy - 10y² - 9

Answered by ace6608
2

= 4x² + 7xy + 3y² + 1 + 2x² - 5xy - 2y² + 8

= 6x² + 2xy + y² + 9

= 9x² - 8xy + 11y² - ( 6x² + 2xy + y² + 9 )

= 9x² - 8xy + 11y² - 6x² - 2xy - y² + 9

= 3x² - 10xy - 10y² - 9

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