Question

Subtract the sum of (4a - 3b - 2) and (3a - 2b + 3) from the sum of (a + b +3 ) and (2b-3a + 5)​

Answer 1

Step-by-step explanation:

5a-2b+9

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Answer 2

Answer:

$8b-9a+5$

Step-by-step explanation:

$[(a+b+3)+(2b-3a+3)]-[(4a-3b-2)+(3a-2b+3)]$

⇒ $(a+b+3+2b-3a+3)-(4a-3b-2+3a-2b+3)$

⇒ $(a-3a+b+2b+3+3)-(4a+3a-2b-3b-2+3)$

⇒ $(3b-2a+6)-(7a-5b+1)$

⇒ $3b-2a+6-7a+5b-1$

⇒ $3b+5b-2a-7a+6-1$

⇒ $8b-9a+5$

∴

$[(a+b+3)+(2b-3a+3)]-[(4a-3b-2)+(3a-2b+3)]=8b-9a+5$