Question

Subtract the sum of (4a-7b+2c) and (3a+6b+3c) from the sum of (6a-4b+3c) and (2a-3c-4b)​

Answer 1

Answer:

Step-by-step explanation:

Sum of (4a - 7b + 2c ) and ( 3a +6b +3c )

4a -7b + 2c + 3a +6b +3c

= (4a + 3a ) + ( -7b + 6b ) + 2c + 3c (∵ like terms adding )

= 7a + ( - b ) +5c

= 7a - b + 5c

Next ,the sum of ( 6a - 4b + 3c ) and ( 2a - 3c - 4b )

6a - 4b + 3c + 2a - 4b - 3c

= ( 6a + 2a ) + (- 4b - 4b ) + ( 3c - 3c ) ( ∵ like terms adding )

= 8a + ( - 8b ) + 0 (∵ adding : - 4 -4 = -8 ; 3c 3c = 0 )

= 8a - 8b ( ∵ + × - = - )

Now subtract ( 7a - b + 5c ) from ( 8a - 8b )

8a - 8b - ( 7a - b + 5c )

= 8a - 8b - 7a + b - 5c ( ∵ - × + = - ; - × - = + )

= ( 8a - 7a ) + ( - 8b + b ) - 5c ( ∵ like terms )

= a + ( - 7b ) - 5c

= a - 7b - 5c is the answer. ( ∵ + × - = - )

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