Subtract the sum of 4a2
– 3a + 5 and 2a2
– 5a – 7 from the sum of
5a2 – 10a + 3 and 2a2
– a - 1
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Answered by
1
Step-by-step explanation:
Sum of 4a2 + 3 – 8a and 9a – 7
= 4a2 + 3 – 8a + 9a – 7 = 4a2 + a – 4
∴ (4a2 + a – 4) – (-5a2 – 3a + 1)
= 4a2 + a – 4 + 5a2 + 3a – 1
= 4a2 + 5a2 + a + 3a – 4 – 1
= 9a2 + 4a – 5
Answered by
2
Answer:
MY paper is going on sorry. But I will answer you after paper.
Step-by-step explanation:
BYE.
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