Math, asked by syedazebaazam, 5 months ago

Subtract the sum of 4x² + 7xy + 3y² + 1 and 2x² - 5xy – 2y² + 8 from 9x² - 8xy + 11y² + 12

Answers

Answered by ahujatanu77
0

Answer:10xy - 3x²- 10y² -3

Step-by-step explanation:

sum of 4x² + 7xy + 3y² + 1 and 2x² - 5xy – 2y² + 8

= 4x² +2x² +7xy-5xy+3y² - 2y²+1+8

=6x² + 2xy +y² +9 - (9x² - 8xy + 11y² + 12)

=6x² + 2xy +y² +9 - 9x² + 8xy - 11y² +12 (The signs change when the brackets open)

=6x² - 9x² +2xy +8xy +y² - 11y² + 9 - 12

-3x²+10xy - 10y² -3

10xy - 3x²- 10y² -3

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