Question

subtract the sum of 4x²y-3xy²+4 and -3x²y-7xy²-7 from x²+4

Answer 1

$\bf \: Sum \: of \: 4 {x}^{2} y - 3x {y}^{2} + 4 \: and \: \\ \bf \: - 3 {x}^{2} y - 7x {y}^{2} - 7 \\ \\ = (4 {x}^{2} y - 3x {y}^{2} + 4) + ( - 3 {x}^{2} y - 7x {y}^{2} - 7) \\ \\ = 4 {x}^{2} y - 3x {y}^{2} + 4 - 3 {x}^{2} y - 7x {y}^{2} - 7 \\ \\ = {x}^{2} y - 10x {y}^{2} - 3 \\ \\ \bf \: Subtracting \: the \: sum \: from \\ \bf \: {x}^{2} + 4 \: we \: get \\ \\ = ( {x}^{2} + 4) - ( {x}^{2} y - 10x {y}^{2} - 3) \\ \\ = {x}^{2} + 4 - {x}^{2} y + 10x {y}^{2} + 3 \\ \\ = - {x}^{2} y + 10x {y}^{2} + {x}^{2} + 7$

If any doubt, please ask :)

Answer 2

Hola Mate!!

Here's your answer :-

$( {x}^{2} + 4) - (4 {x}^{2} y- 3x {y}^{2} + 4 + ( - 3) {x}^{2} y - 7x {y}^{2} - 7) \\ = > {x}^{2} + 4 - ( {x}^{2}y - 10x {y}^{2} - 3) \\ = > {x}^{2} + 4 - {x}^{2}y + 10x {y}^{2} + 3 \\ = > {x}^{2} + 7 - {x}^{2} y + 10x {y}^{2}$

hope it helps
Mark me as brainliest if it's correct ^_^