Math, asked by visheshp69, 6 months ago

Subtract the sum of (4x³ + 2x² - 5) and (15x-x³-x²) from the sum of (9 + 6x-2x²) and
(4X – 1 – 5x³ + x²).​

Answers

Answered by tanushreedatta1234
11

Answer:

here the ans, 8x³+2x²+5x-13

Attachments:
Answered by BrookTheBigBrain
8

Answer:

−8x³−2x²−5x+13

Step-by-step explanation:

The sum of (4x³ + 2x² - 5) and (15x-x³-x²):

4x³+2x²-5+15x-x³-x²

Simplify

3x³+x²+15x−5

New problem: Subtract 3x³+x²+15x−5 from the sum of (9 + 6x-2x²) and

(4X – 1 – 5x³ + x²).​

Sum of (9 + 6x-2x²) and (4X – 1 – 5x³ + x²):

9 + 6x-2x²+4X – 1 – 5x³ + x²

Simplify

-5x³-x²+10x+8

New problem: Subtract 3x³+x²+15x−5 from -5x³-x²+10x+8

-5x³-x²+10x+8-(3x³+x²+15x−5)

Distribute

-5x³-x²+10x+8-3x³-x²-15x+5

Simplify

−8x³−2x²−5x+13

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