Question

Subtract the sum of 4x3-3x2+4x-1 and 3x+4x2+5x3-8 from the sum of 8x3+x+1
and 2x2+4x. pls give clearly

Answer 1

Answer:

• 9
• 31
• 27
• 36

Step-by-step explanation:

you have to only calculate this ex 4×3-3×2+4-2+1

Answer 2

To find: Subtract the sum of 4×3-3×2+4x-1 and 3x+4×2+5×3-8 from the sum of 8×3+x+1 and 2×2+4x

Solution: We can simply solve this mathematical problem by using the following mathematical process.

According to BODMAS Rule,

4×3-3×2+4x-1 = 12-6+4x-1 = 6+4x-1 = 4x+5

3x+4×2+5×3-8 = 3x+8+15-8 = 3x+15

8×3+x+1 = 24+x+1 = x+25

2×2+4x = 4x+ 4

 The sum of the first two terms will be : 4x+5+3x+15 = 7x+20

 The sum of the second two terms will be : x+25+4x+4 = 5x+29

Now subtracting the first two terms from the second two terms we will get,

5x+29-(7x+20) = 5x+29-7x-20= -2x+9

So, the answer will be: -2x+9 (Ans)