Subtract the sum of 5a²+a-3 and a²-3a+7 from 6a²+a-2
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Answer:
a=2 or -3a+6=0
Step-by-step explanation:
5a²+a-3
a²-3a+7
Totally 6a²-2a+4
6a²-2a+4-(6a²+a-2)=0
6a²-2a+4-6a²-a+2=0
-3a+6=0
a=-6*-1/3
a=2
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