Subtract the sum of 5x-4y+ 6z and -8x+y-2z from the sum of 12x-y+3z and -3x+5y-8z.solve with statement.
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★ ARITHMETICS ★
Sum of above acquired quantity -
5x - 4y + 6z + ( -8x + y - 2z ) =
-3x -3y + 4z
Second sum -
12x - y + 3z + ( -3x + 5y -8z ) =
9x + 4y - 5z
Now , subtracting first sum from the another one ,
9x + 4y - 5z - ( -3x -3y + 4z ) =
12x + 7y - 9z
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Sum of above acquired quantity -
5x - 4y + 6z + ( -8x + y - 2z ) =
-3x -3y + 4z
Second sum -
12x - y + 3z + ( -3x + 5y -8z ) =
9x + 4y - 5z
Now , subtracting first sum from the another one ,
9x + 4y - 5z - ( -3x -3y + 4z ) =
12x + 7y - 9z
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bhavani9:
thank u and nice explation
Answered by
12
[(12x-y+3z)+(-3x+5y-8z)]-[(5x-4y+6z)+(-8x+y-2z)]
(12x-y+3z-3x+5y-8z)-(5x-4y+6z-8x+y-2z)
(9x+4y-5z)-(-3x-3y+4z)
9x+4y-5z+3x+3y-4z
12x+7y-9z
(12x-y+3z-3x+5y-8z)-(5x-4y+6z-8x+y-2z)
(9x+4y-5z)-(-3x-3y+4z)
9x+4y-5z+3x+3y-4z
12x+7y-9z
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