Question

subtract the sum of (-6/11) and 10/33 from the sum of 5/9 and (-3/33)​

Answer 1

Answer:

54/99 or 6/11

Step-by-step explanation:

sum of (-6/11) and 10/33:

$- \frac{6}{11} + \frac{10}{33} = \frac{ - 18 + 10}{33} = \frac{ - 8}{33}$

sum of 5/9 and (-3/33):

$\frac{5}{9} + ( \frac{ - 3}{33} ) = \frac{5}{9} + ( \frac{ - 1}{11} ) = \frac{55 - 9}{99} = \frac{46}{99}$

subtract -8/33 from 46/99:

$\frac{46}{99} - ( \frac{ - 8}{33} ) = \frac{46}{99} + \frac{8}{33} = \frac{46 + 8}{99} = \frac{54}{99} = \frac{6}{11}$