Question

Subtract the sum of 6 2/5 and 3 1/4 from 12​

Answer 1

Answer:

6 2/5=32/5.

3 1/4=13/4

SUM:

32/5+13/4

(128+65)/20

193/20

DIFFERENCE:

12-193/20

(240-193)/20

47/20=2 7/20

Step-by-step explanation:

HOPE THIS WILL HELP YOU:)

Answer 2

$\large \orange \bigstar \red{ \underline{ \underline{ \green{Solution :}}}}$

$\: \: \: \: \: \: \rightarrow \: \: { \purple{6 \large \frac{2}{5} \small + 3 \large \frac{1}{4} }}$

$\implies \: \large \frac{32}{5} + \frac{13}{4}$

$\implies \: \large \frac{128 + 65}{20}$

$\boxed{ = \frac{193}{20} } \rightarrow \: \: \green{is \: \: the \: \: sum.}$

$\large \orange{ \underline{ \underline \pink{subtraction : }}}$

$\mathrm{ \implies \: 12 - \large\frac{193}{20} }$

$\implies \: \large\frac{240 - 193 }{20}$

$\implies \: \large \red{ \frac{ 47}{20} }$

$\therefore \: \rm \boxed{ \green{\frac{ 47}{20} }} \: \: \purple{is \: \: the \: \: answer..}$