Question

Subtract the sum of 6a−6c + 3b&7c−4b+13a from the sum of 2a−7 + 4b & 6a−4c−4b.

Answer 1

Answer:

3a+4b+7c,−5a+3b−6c and 4a−2b−4c

The sum of 3a+4b+7c,−5a+3b−6c and 4a−2b−4c is calculated as shown below

(3a+4b+7c)+(−5a+3b−6c)+(4a−2b−4c)

=3a+4a−5a+4b+3b−2b+7c−6c−4c

We get,

=2a+5b−3c

Hence, the sum of 3a+4b+7c,−5a+3b−6c and 4a−2b−4c is 3c