Subtract the sum of -6b+c+a and -3a+2c + 3b
from the sum of 5a - 8b+2c and 3c - 4b - 2a.
Answers
Answer:
Check the attachment!
- 6b + c + a
- 3a + 2c + 3b
We have to do the sum of both the equations.
i.e.
→ - 6b + c + a + (- 3a + 2c + 3b)
→ - 6b + c + a - 3a + 2c + 3b
→ -6b + 3b + c + 2c + a - 3a
→ - 3b + 3c - 2a
→ - 2a - 3b + 3c __________ (eq 1)
Similarly,
Do the sum of 5a - 8b + 2c and 3c - 4b - 2a.
→ 5a - 8b + 2c + (3c - 4b - 2a)
→ 5a - 8b + 2c + 3c - 4b - 2a
→ 5a - 2a - 8b - 4b + 2c + 3c
→ 3a - 12b + 5c ________ (eq 2)
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Let's return to the question i.e. Subtract the sum of -6b+c+a and -3a+2c + 3b
from the sum of 5a - 8b+2c and 3c - 4b - 2a.
Sum of - 6b + c + a and - 3a + 2c + 3b is - 2a - 3b + 3c
And sum of 5a - 8b + 2c and 3c - 4b - 2a. is 3a - 12b + 5c.
Now, subtract the sum of both given equations.
i.e.
(eq 2) - (eq 1)
→ 3a - 12b + 5c - (- 2a - 3b + 3c)
→ 3a - 12b + 5c + 2a + 3b - 3c
→ 3a + 2a - 12b + 3b + 5c - 3c
→ 5a - 9b + 2c
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5a - 9b + 2c
_______ [ANSWER]
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