Math, asked by shlokkumar98, 11 months ago


Subtract the sum of -6b+c+a and -3a+2c + 3b
from the sum of 5a - 8b+2c and 3c - 4b - 2a.​

Answers

Answered by shivangi2506
42

Answer:

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Answered by Anonymous
58

- 6b + c + a

- 3a + 2c + 3b

We have to do the sum of both the equations.

i.e.

→ - 6b + c + a + (- 3a + 2c + 3b)

→ - 6b + c + a - 3a + 2c + 3b

→ -6b + 3b + c + 2c + a - 3a

→ - 3b + 3c - 2a

- 2a - 3b + 3c __________ (eq 1)

Similarly,

Do the sum of 5a - 8b + 2c and 3c - 4b - 2a.

→ 5a - 8b + 2c + (3c - 4b - 2a)

→ 5a - 8b + 2c + 3c - 4b - 2a

→ 5a - 2a - 8b - 4b + 2c + 3c

3a - 12b + 5c ________ (eq 2)

___________________________

Let's return to the question i.e. Subtract the sum of -6b+c+a and -3a+2c + 3b

from the sum of 5a - 8b+2c and 3c - 4b - 2a.

Sum of - 6b + c + a and - 3a + 2c + 3b is - 2a - 3b + 3c

And sum of 5a - 8b + 2c and 3c - 4b - 2a. is 3a - 12b + 5c.

Now, subtract the sum of both given equations.

i.e.

(eq 2) - (eq 1)

→ 3a - 12b + 5c - (- 2a - 3b + 3c)

→ 3a - 12b + 5c + 2a + 3b - 3c

→ 3a + 2a - 12b + 3b + 5c - 3c

5a - 9b + 2c

___________________________

5a - 9b + 2c

_______ [ANSWER]

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