Math, asked by shreyasachan11, 4 months ago

Subtract the sum of 6x – 7y + 8xy – 5z and 5x + 9y – 2xy from the sum of 3y – 2x + xy – z

and –6xy – 5y + 4z.
pls answer fast how will ans this before 11:20 I will mark give him/her 5 point pls fast ​

Answers

Answered by nivedhahere48
0

Answer

( 1y - 8x + 7xy - 6z)

Explaination:

Subtract the sum of(6x - 7y + 8xy - 5z + 9y - 2 xy) from the sum ( 3y - 2x + xy - z )

(6x - 7y + 8xy - 5z + 9y - 2 xy) from(3y -2x +xy - z )

So, (3y -2x +xy - z ) -(6x-7y + 8xy - 5z + 9y - 2 xy)

(3y -2x +xy - z ) - ( 6x - 2y + 6xy - 5z )

And put the plus sign outside then the minus sign goes in like this( this step is to make tje sum more easier) ;

(3y -2x +xy - z ) + ( -6x - 2y + 6xy - 5z )

( 1y - 8x + 7xy - 6z)

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