SUBTRACT THE SUM OF-7/15 AND-5 FROM 2/9
Answers
Answer:
PREMISES
y=(5/2+-11/12)-(-5/7+-8/3)
CALCULATIONS
(1) y=(5/2+-11/12)-(-5/7+-8/3) (Find the LCD and convert the fractions)
LCD=the product of the greatest number of times any prime factor appears in the prime factors of all of the denominators=2×2×3×7=84
(2) y= [(42×5)/84+(7×-11)/84]-[(12×-5)/84+(28×-8)/84]
(3) y=(210/84+-77/84)-(-60/84+-224/84)
(4) y=[(210–77)/84]-[(-60–224)/84)
(5) y=(133/84)-(-284/84) *** [a- (-b)=a+b; so -(-284/84) becomes +(284/84) in the calculations that follow, which see]
(6) y=133/84+(284/84) ***
(7) y=(133+284)/84
(8) y=417/84 (Simplify by cancelling common factors in the numerator and denominator)
(9) y=
139/28
C.H.
Step-by-step explanation:
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Sum
-7/15+(-5)
= - 7 + (-3)/15
= (- 7 - 3)/15
= - 10/15
= - 2/3
Now,
Subtraction
2/9 - (-2/3)
= 2/9 + 2/3
= (2 + 6)/9
= 8/9