Question

Subtract the sum of -8/9 and 3/2 from the sum of 11/-18 and -1/36. ​

Answer 1

Answer:

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$( - \frac{8}{9} + \frac{3}{2} ) - ( - \frac{11}{18} + (- \frac{ 1}{36} )$

$( - \frac{(8 \times 2) + (3 \times 9}{18}) - ( - \frac{(11 \times 2) - 1}{36} )$

$( \frac{ ( - 16) + 27}{18} ) - ( \frac{ - 22 - 1}{36} )$

$( \frac{11}{18} ) - ( - \frac{23}{36} )$

$\frac{(11 \times 2) - ( - 23)}{36}$

$\frac{22 + 23}{36}$

$\frac{45}{36}$

$\frac{5}{4}$

Answer 2

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Subtract the sum of -8/9 and 3/2 from the sum of 11/-18 and -1/36.

$\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$

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FINDING SUM:-

$= > - \frac{8}{9} + \frac{3}{2}$

=>L.C.M OF 9& 2 IS 18

$= > \frac{ - 16 + 27}{18} = \frac{11}{18}$

$= > - \frac{11}{18} + ( - ) \frac{1}{36}$

$= > - \frac{11}{18} - \frac{1}{36}$

L.C.M OF 18 & 36 IS 36

$= > \frac{ - 22 - 1}{36} = - \frac{23}{36}$

Subtracting the sum of -8/9 and 3/2 from the sum of 11/-18 and -1/36.

$= > \frac{11}{18}( -) - \frac{23}{36}$

$= > \frac{11}{18} + \frac{23}{36}$

L.C.M OF 18 & 36 IS 36

$= > \frac{22 + 23}{36} = \frac{45}{36} = \frac{15}{12} = \frac{5}{4}$

Answer is 5/4 ✓

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