Question

Subtract the sum of 8a-5b-7c and -6a+7b-4c from the sum of 6a+2b-3c and -2a+4b-8c.

Answer 1

Answer:

Firstly add 8a-5b-7c + (-6a +7b -4c)

8a-5b-7c -6a +7b -4c

2a +2b -11c

now add 6a+2b-3c + ( -2a+4b-8c)

6a +2b-3c -2a +4b-8c

4a +6b -11c

Now subtract 2a+2b-11c from 4a+6b -11c

4a+6b-11c -(2a+2b-11c)

4a+6b -11c -2a-2b+11c

2a +4b

Answer 2

Answer: - 2a-4b

Step-by-step explanation: ATQ, we have to do this:-[ { (8a-5b-7c) + (-6a+7b-4c)} - { (6a+2b-3c) + (- 2a+4b-8c)}]

We have add to get the required 'sum'

(8a-5b-7c)+(-6a+7b-4c)

Rearranging and combining like terms

=> 8a-6a-5b+7b-7c-4c

=> 2a+2b-11c

Similarly,

(6a+2b-3c) +(- 2a+4b-8c)

=> 6a-2a+2b+4b-3c-8c

=> 4a+6b-11c

Subtracting both the sums

(2a+2b-11c) - (4a+6b-11c)

We have put brackets in subtraction, so the signs of all the terms in the second sum'll change.

=> 2a-4a+2b-6b-11c+11c

Since, - a+a=0

Therefore=> - 2a-4b