subtract the sum of (8a - 6a2 + 9) and (-10a - 8 + 8a2) from -3
(a2 = a square = a*a)
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Answer:
8a - 6 a^2 + 9 + ( -10a -8 + 8a^2 )
= 8a - 6a^2 + 9 -10a - 8 + 8a^2
= 8a -10a - 6a^2 + 8a^2 + 9 - 8
= -2a + 2a^2 + 1
-3 - ( -2a + 2a^2 + 1)
= -3 + 2a - 2a^2 - 1
= -3 -1 + 2a - 2a^2
= -4 + 2a - 2a^2
I hope it is helpful
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