Question

Subtract the sum of (8a3 + 4a + 5c2

) and (4a2 + 8b – 4c2

) from (−2a3 + 9a

− 5c2 + 8a2 + 6) ​

Answer 1

Answer:

I DON'T KNOW

I HOPE IT HELPFUL

Answer 2

Answer:

= 10a3 - 5a + 6c2 - 4a2 - 8b - 6

Step-by-step explanation:

8a3 + 4a + 5c2 added to -4c2 + 4a2 + 8b=

= 8a3 + 4a + 1c2 + 4a2 + 8b

8a3 + 4a + 1c2 + 4a2 + 8b subtracted from -2a3 + 9a -5c2 + 8a2 + 6=

=10a3 - 5a + 6c2 - 4a2 - 8b - 6

hope it helps :)