Question

Subtract the sum of (8m − 7n + 6p 2 ) and (−3m − 4n − p 2 ) from the sum of
(2m + 4n − 3p 2 ) and (− m − n − p 2 ).

SOLVE

Answer 1

Answer:

(8m-7n+6p 2) and (-3-4n-p2) from the sum of

(2m+4n-3p2) and (-m_n-p2)

Step-by-step explanation:

5m-11n+6p2

2m+4n-3p2

Answer 2

Answer:

Step-by-step explanation:

The sum of

( 8m - 7n + 6p² ) + ( - 3m - 4n - p² )

= ( 8m - 3m ) + ( - 7n - 4n ) + ( 6p² - p² ) (∵like terms adding )

= 5m + ( - 11n ) + 5p²

= 5m - 11n + 5p² ( ∵ + × - = - )

Now another sum of

( 2m + 4n - 3p² ) + ( - m - n - p² )

= ( 2m - m ) + ( 4n - n ) + ( - 3p² - p² ) (∵ like terms adding )

= m + 3n + ( - 4p² )

= m + 3n - 4p² ( ∵ + × - = -)

On subtracting ( 5m - 11n + 5p² ) from ( m + 3n - 4p² )

( m + 3n - 4p² ) - (5m - 11n + 5p² )

= m + 3n - 4p² - 5m + 11n - 5p² ( ∵ - × + = - ; - × - = + )

= ( m - 5m ) + ( 3n + 11n ) + ( - 4p² - 5p² )

= - 4m + 14n + ( - 9p² )

= - 4m + 14n - 9p² is the answer. ( ∵ + × - = - )