Question

Subtract the sum of (8m – 7n + 6p) and (-3m - 4n - p') from the sum of (2m + 4n - 3p') and
(-m - n-p)


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Answer 1

Answer:

(8m−7n+6p

2

)+(−3m−4n−p

2

)=(8−3)m−(7+4)n+(6−1)p

2

=5m−11n+5p

2

⟹(1)

(2m+4n−3p

2

)+(−m−n−p

2

)=(2−1)m+(4+1)n−(3+1)p

2

=(2−1)m+(4−1)n−(3+1)p

2

⟹(2)

Subtracting(1)from(2)

(m+3n−4p

2

)−(5m−11n+5p

2

)=(1−5)m+(3+11)n−(4+5)p

2

=−4m+14n−9p

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