Math, asked by sonal107149, 2 months ago

Subtract the sum of (8m - 7n + 6p2) and (- 3m - 4n-p) from the sum of (2m + 4n - 3p2
and (-m -n- p2)​

Answers

Answered by nudratebad132
2

Step-by-step explanation:

First add (8m-7n+6p²) and (-3m-4n-p)

= (8m-7n+6p²)+(-3m-4n-p)

= 8m-7n+6p²-3m-4n-p

= 8m-3m-7n-4n-p+6p²

= 5m-11n-p+6p²-------eq 1

Now Add (2m+4n-3p²) and (-m-n-p²)

= (2m+4n-3p²)+(-m-n-p²)

= 2m+4n-3p²-m-n-p²

= 2m-m+4n-n-p²-3p²

= -4p²+m+3n--------eq 2

Now subtract equation 1 from equation 2:

= (-4p²+m+3n)-(5m-11n-p+6p²)

= -4p²+m+3n-5m+11n+p-6p²

= -4p²-6p²+m-5m+3n+11n+p

= -10p²-4m+14n+p

ANSWER!

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