Question

subtract the sum of (8m -7n+6p²)and (-3m-4n -p²) from the sum of (2m + 4n-3p²) and (-m-n-p²).​

Answer 1

Answer:

-4m+15n-6p²

Step-by-step explanation:

(2m+4n-3p²)+(-m-n-p²)

= 2m+4n-3p²-m-n-p²

= m+3n-4p²----------------(1)

(8m-7n+6p²)+(-3m-4n-p²)

=8m-7n+6p²-3m-4n-4p²

=5m-12n+2p²-----------------(2)

sub 2 from 1,

=(m+3n-4p²)-(5m-12n+2p²)

=m+3n-4p²-5m+12n-2p²

=-4m+15n-6p²

Answer 2

Answer:

-4m + 14n - 9p²

Explanation:

S₁ = (8m -7n + 6p²) + ( - 3m-4n -p²) = 8m - 7n + 6p²- 3m - 4n -p² = 5m - 11n + 5p²

S₂ = (2m + 4n - 3p²) + ( - m-n-p²) = 2m + 4n - 3p²- m - n-p²= m + 3n - 4p²

S₂-S₁ = (m+3n-4p²) - (5m-11n+5p²) = m + 3n - 4p² - 5m + 11n - 5p²= - 4m + 14n - 9p²

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