Math, asked by Anonymous, 8 months ago

Subtract the sum of 8x - 5y - 2z and -6x +8y - 4z from the sum of 6x+ 2y - 4z and -2x + 4y - 8z.
please don't spam coz tomorrow is my test. The answer should be the.. it is given in the image. Please solve it step by step ​

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Answers

Answered by ramyanagineni
3

Answer:

sum1=8x-5y-2z+(-6x+8y-4z)

        =(8x-6x)+(-5y+8y)+(-2z-4z)

        =2x+3y-6z

sum2=6x+2y-4z+(-2x+4y-8z)

        =(6x-2x)+(2y+4y)+(-4z-8z)

        =4x+6y-12z

result=sum2-sum1

        =4x+6y-12z-(2x+3y-6z)

        =4x+6y-12z-2x-3y+6z

        =(4x-2x)+(6y-3y)+(-12z+6z)

        =2x+3y-6z

Step-by-step explanation:

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