Question

Subtract the sum of 9b2-3c2 and 2b2-2c2+bc from 2b2-2bc-c2

Answer 1

Step-by-step explanation:

% 3D 962 - 3c2 +262 + bc - 2c2 962 +262 3c2 - 2c2 + bc 1162 - 5c2 + bc% 3D 262 - 2bc c2 + c2 + 2 - 62 = 262 - 62 - 2bc + 0 = 62 - 2bc now, (62 - 2bc) - (1162 - 5c² + bc) = 62 - 2bc - 1162 + 5c2 - bc = 62 - 1162 2bc - bc + 502 -1062 - 3bc + 5c2% 3D

Answer 2

Answer:

9b² - 3c² + 2b² +bc - 2c² =

9b² +2b² - 3c² - 2c² + bc =

11b² - 5c² + bc

2b² - 2bc - c² + c² + 2 - b² =

2b² - b² - 2bc + 0 = b² - 2bc

now,

(b² - 2bc) -(11b² - 5c² + bc) =

b² - 2bc - 11b² - 2bc - bc + 5c² =

-10b² - 3bc + 5c²

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