Subtract the sum of 9b²- 3c² and 2b²+ bc- 2c² from the sum of 2b²- 2bc- c² and c²+ 2bc- b² .
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Answer:
10b²-5c²+bc
Step-by-step explanation:
(9b²-3c²+2b²+bc-2c² ) - (2b²- 2bc- c² + c²+ 2bc- b²)
=(11b²-5c²+bc) - (b²)
=10b²-5c²+bc
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Ans:- [(2b²- 2bc- c²)+(c²+ 2bc- b²)] - {(9b²- 3c²)+(2b²+ bc- 2c²)}.
= [2b²- 2bc- c²+c²+ 2bc- b²] - {9b²- 3c²+2b²+ bc- 2c²}
= [b²] - {11b²- 5c²+bc}.
= b²- 11b²- bc + 5c²
= 5c² - bc - 10b².
here is your answer
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