Question

subtract the sum of a+2b-3cand2c-3b-4a from the sum of 5b-4c+a and 2c-3b-4a.

Answer 1

Step-by-step explanation:

STEP 1:

(a+2b–3c)+(2c–3b–4a)

=(–3a–1b–1c)

STEP 2:

(5b–4c+a)+(–3b+2c–4a)

=(2b–2c–3a)

STEP 3:

(2b–2c–3a)–(–3a–1b–1c)

(2b–2c–3a)+(+3a+1b+1c)

=3b–1c

HOPE THE ANSWER HELPS YOU ☺️☺️

Answer 2

Firstly, add a + 2b - 3c and 2c - 3b - 4a

$(a + 2b - 3c) + (2c - 3b - 4a)$

$= a + 2b - 3c + 2c - 3b - 4a$

$= (a - 4a) + (2b - 3b) + (2c - 3c)$

$= - 3a - b - c$

Now add 5b - 4c + a and 2c - 3b - 4a

$= (5b - 4c + a) + (2c - 3b - 4a)$

$= 5b - 4c + a + 2c - 3b - 4a$

$=(5b - 3b) + (2c - 4c) + (a - 4a)$

$= 2b - 2c - 3a$

Now Subtract -3a - b - c from 2b - 2c - 3a

$=(2b - 2c - 3a) - (- 3a - b - c)$

$= 2b - 2c - 3a + 3a + b + c$

$= (2b + b) + (c - 2c) + (3a - 3a)$

$= 3b - c + 0$

$= 3b - c$

Hope you understand...