Question

Subtract the sum of a(a + 2b + c) and -b/a – b + 2c) from c(- a - b + c)​

Answer 1

Answer:

a² + b² - c² + ab - bc + 2ac

Step-by-step explanation:

according to the question, we need to find the sum of the two terms firstly...

i. e.,

a(a + 2b + c) + [-b(a - b + 2c)]

= a(a + 2b + c) - b(a - b + 2c)

= a² + 2ab + ac - ab + b² - 2bc

= a² + b² + ab - 2bc + ac

now the difference,

(a² + b² + ab - 2bc + ac) - c(-a - b + c)

= a² + b² + ab - 2bc + ac + ac + bc - c²

= a² + b² - c² + ab - bc + 2ac