Subtract the sum of a² + 2b² - c² and 3b² +5c² - 9a² from the sum of 11a² - 7b² - 3c² and 2a² +13b² + 16c
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Step-by-step explanation:
a²+2b²-c²+3b²+5c²-9a² = a²-9a²+2b²+3b²-c²+5c²
= -8a²+5b²-4c²
11a²-7b²-3c²+2a²+13b²-16c² = 11a²+2a²-7b²+13b²-3c²-16c²
= 13a²+6b²-19c²
11a²-7b²-3c²+2a²+13b²-16c²-(a²+2b²-c²+3b²+5c²-9a² )
= 13a²+6b²-19c²- (-8a²+5b²-4c²)
= 13a²+6b²-19c²+8a²-5b²+4c²
= 21a²+b²-15c²
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