subtract the sum of ( a²_3a) and 7 from from the sum of 3a² and 2a _ 2
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Answer:
The sum of a2−3a and 7 is a2−3a+7 and the sum of 3a2 and 2a−2 is 3a2+2a−2.
We know that Like terms are terms that contain the same variables raised to the same power.
We group together the like terms and subtract a2−3a+7 from 3a2+2a−2 as follows:
(3a2+2a−2)−(a2−3a+7)=3a2+2a−2−a2+3a−7=(3a2−a2)+(2a+3a)+(−2−7)=2a2+5a−9
Hence, (3a2+2a−2)−(a2−3a+7)=2a2+5a−9.
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Answer:
2a^2+5a-9
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