Question

Subtract the sum of the expressions.
3ab + 2ac – 3bc and 6bc - 4ac + 2ab from
5ab- 4ac + 7bc.​

Answer 1

Answer:

-2ac+4bc

Explanation:

sum of(3ab+2ac-3bc) and ( 6bc-4ac+2ab) is:

3ab+2ac-3bc+(6bc-4ac+2ab)

=3ab+2ab+2ac-4ac-3bc+6bc

=5ab-2ac+3bc

this has to subtracted from (5ab-4ac+7bc

so we have:

5ab-4ac+7bc-(5ab-2ac+3bc)

=5ab-4ac+7bc-5ab+2ac-3bc

=5ab-5ab-4ac+2ac+7bc-3bc

=-2ac+4bc

Answer 2

Answer:

-2ac+4bc

Explanation:

Sum of (3ab + 2ac - 3bc) and (6bc - 4ac + 2ab) is:

3ab + 2ac3bc + (6bc - 4ac + 2ab)

= 3ab + 2ab + 2ac - 4ac - 3bc + 6bc

=

5ab2ac + 3bc

This has to be substracted from (5ab - 4ac + 7bc)

So, we have:

5ab- 4ac + 7bc - (5ab - 2ac + 3bc)

= 5ab - 4ac + 7bc - 5ab + 2ac - 3bc

= 5ab5ab - 4ac + 2ac + 7bc - 3bc

= -2ac + 4bc