Subtract the sum of x+y and y+z The sum of 2x+3y and 3y +4z
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Answer:
x+4y+3z
Step-by-step explanation:
if your question is subtract the sum of x+y and y+z from the sum of 2x+3y and 3y+4z
then the solution is ,
((2x+3y)+(3y+4z))-((x+y)+(y+z))
= (2x+6y+4z)-(x+2y+z)
=(2x-x)+(6y-2y)+(4z-z)
=x+4y+3z
hope it helps
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