Subtract the sum of x2 −3xy−15y2 and 2x2 +xy−2y2 from the sum of 2xy−8x2 −3y2 and −5x2 −3xy+5y2.
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Answer:
answer to above is xy-16x²+19y²
Step-by-step explanation:
Step 1 x²-3xy-15y²+2x²+xy-2y²
=x²+2x²-3xy+xy-15y²-2y²
=3x²-2xy-17y²
step 2 2xy+8x²-3y²-5x²-3xy+5y²
=2xy-3xy-8x²-5x²-3y²+5y²
-xy-13x²+2y²
Step 3 -xy-13x²+2y²-(3x²-2xy-17y²)
= -xy -13x²+2y²-3x²+2xy+17y²
= -xy+2xy-13x²-3x²+2y²+17y²
= xy-16x²+19y²
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