Subtract the sum of x2 – 5xy + 2y2 and y2 – 2xy – 3x2 from the sum of 6x2 – 8xy - y2 and
2xy - 2y2 - x2
Answers
Answered by
10
Answer:
➡️ (6x² - 8xy - y² + 2xy - 2y² - x² )- (x²-5xy + 2y² + y² - 2xy - 3x² )
➡️ ( 6x² - x² - 8xy + 2xy - y² - 2y² ) - ( x² - 3x² - 5xy - 2xy + 2y² + y²)
➡️ 5x² - 6xy - 3y² - ( -2x² - 7xy + 3y²)
➡️ 5x² - 6xy - 3y² + 2x² + 7xy - 3y²
➡️ 5x² + 2x² - 6xy + 7xy - 3y² - 3y²
➡️ 7x² + xy - 6y²
Answered by
0
Answer:
-7x²+2y²-13xy
Step-by-step explanation:
SUM:-
x²-5xy+2y²+y²-2xy-3x²
-5xy+2y²+y²-2xy-3x²x²-3x²+2y²+y²-5xy-2xy
-2x²+3y²-7xy
SUM:-
6x²-8xy-y²+2xy-2y²-x²
6x²-x²-y²-2y²+2xy-8xy
5x²-y²-6xy
DIFFERENCE:-
-2x²+3y²-7xy-5x²-y²-6xy
-2x²-5x²+3y²-y²-7xy-6xy
[-7x²+2y²-13xy]
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