Question

Subtract the sum of (- x⁴ + 13x⁵ + 6 x) and (6x³+5x⁵+ 7x⁴) from ( 19x⁴ + 7 x⁵ - 2x³)​

Answer 1

Answer:- 1

$- 11x {}^{5} + 13x {}^{4} - 8x {}^{3} - 6x$

please mark as brainlist answer.

Answer 2

Step-by-step explanation:

(19x^4+7x^5-2x^3)-{(-x^4+13x^4+6x)+(6x^3+5x^5+7x^4)}

=(19x^4+7x^5-2x^3)-{(12x^4+6x)+(6x^3+5x^5+7x^4)}

=(19x^4+7x^5-2x^3)-{12x^4+6x+6x^3+5x^5+7x^4}

=(19x^4+7x^5-2x^3)-{12x^4+7x^4+6x+6x^3+5x^5}

=(19x^4+7x^5-2x^3)-{19x^4+6x+6x^3+5x^5}

=19x^4+7x^5-2x^3-19x^4-6x-6x^3-5x^5

=19x^4-19x^4+7x^5-5x^5-2x^3-6x^3-6x

=0+2x^5-8x^3-6x

Ans=2x^5-8x^3-6x.

Mark me the brainliest.