Question

subtract the sum og 5/9 and 4/9 from the sum of 7/11 and 3/9​

Answer 1

Sum of 5/9 and 4/9

=>

$\frac{5}{9} + \frac{4}{9} = \frac{9}{9} = 1$

Sum of 7/11 and 3/9

=>

$\frac{7}{11} + \frac{3}{9} = \frac{63 +33 }{99} \\ = \frac{96}{99}$

Subtract

$\frac{96}{99} - 1 \\ = \frac{96 - 99}{99} \\ = \frac{ - 3}{99} = \frac{ - 1}{33}$

Answer 2

Hello!

Question :

subtract the sum of 5/9 and 4/9 from the sum of 7/11 and 3/9

Solution :

$\frac{5}{9 } + \frac{4}{9 } = \frac{9}{9} = 1$

Next,

$\frac{7}{11} + \frac{3}{9} = \frac{32}{33}$

Now,

$\frac{32}{33} - 1 = \frac{ - 1}{33}$

Hope this helps