Question

Subtract
x^2+ 3x + 5 from the sum of 4x^2 + x -6 and 3x^2+ 5x +7​

Answer 1

Step-by-step explanation:

(4x²+x-6)+(3x²+5x+7)-(x²+3x+5)

=(4x²+x-6+3x²+5x+7)-(x²+3x+5)

=(7x²+6x+1)-(x²+3x+5)

=7x²+6x+1-x²-3x-5

=6x²-3x-4

Answer 2

Step-by-step explanation:

Answer

sum of :

4x^2+x-6 and 3x^2+5x+7 is

7x^2+6x+1.

Given to find difference of 7x^2+6x+1 and x^2+3x+5

i.e,7x^2+6x+1-(x^2+3x+5)

=7x^2+6x+1-x^2-3x-5

=6x^2+3x-4.

SO THE ANSWER IS 6x^2+3x-4