subtract x^2-3xy-3/2y^2 and 2x^2+xy
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Answer:
-x²-4xy-3/2y²
Step-by-step explanation:
The question is to subtract x²-3xy-3/2y² and 2x²+xy
so,(x²-3xy-3/2y²)-(2x²+xy)
x²-2x²-3xy-3/2y²-xy
= -x²-4xy-3/2y²
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