Math, asked by kritusharma1919, 8 months ago

Subtract :- x^2-5/2x+7 from 1/3x^2+1/2x+2.​

Answers

Answered by pari2008chitra6153
1

Answer:

x3 + 3x2 + 5x – 4) – (3x3 – 8x2 – 5x + 6)

(x3 + 3x2 + 5x – 4) – 1(3x3 – 8x2 – 5x + 6)

(x3 + 3x2 + 5x – 4) – 1(3x3) – 1 (–8x2) – 1(–5x) – 1(6)

x3 + 3x2 + 5x – 4 – 3x3 + 8x2 + 5x – 6

x3 – 3x3 + 3x2 + 8x2 + 5x + 5x – 4 – 6

–2x3 + 11x2 + 10x –10

And here's what the subtraction looks like, when going vertically:

\small{ \begin{array}{rrrr}x^3&+3x^2&+5x&-4\\-(3x^3&-8x^2&-5x&+6)\\ \hline\end{array} }

x

3

−(3x

3

+3x

2

−8x

2

+5x

−5x

−4

+6)

Answered by jackff
2

Answer:

for fun if u want to join

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