Math, asked by ankitahalbe03, 6 months ago

subtract (x^2 - 5/2x + 7) from (1/3x ^2+1/2x+2)​

Answers

Answered by ag0008699
22

Answer:

1/3x²+1/2x +2 -(x²-5/2x +7)

1/3x²+1/2x +2 -x²+5/2x -7

x²-3x²/3 +x+5x/2 -5

-2x²/3 +6x/2 -5

-2x²/3 +3x-5

Answered by bighnes87
5

\huge\green{A}\red{N}\orange{S}\pink{W}{E}\blue{R}

\huge{[(\frac{1}{3}x)^{2}+\frac{1}{2}x+2]-[x^{2}-\frac{5}{2}x+7]

\huge{(\frac{1}{9}x^{2}+\frac{1}{2}x+2)-(x^{2}-\frac{5}{2}x+7)

\huge{\frac{1}{9}x^{2}+\frac{1}{2}x+2-x^{2}+\frac{5}{2}x-7

\frac{1}{9}x^{2}-x^{2}+\frac{1}{2}x+\frac{5}{2}x+2-7

\frac{-8}{9}x^{2}+\frac{6}{2}x-5

\huge\boxed{\orange{\frac{-18}{9}x^{2}+3x-5}}

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