Math, asked by Anonymous, 10 months ago

Subtract (x^2-5y^2+2z^2) from the sum of (-3x^2-7y^2+z^2), (3x^2-y^2+7z^2) and (-x^2-y^2-2z^2)

Answers

Answered by Ashita1512
1

 {3x}^{2}  -  {7y}^{2}  +  {z}^{2}  +  {3x}^{2}  -  {y}^{2}  +  {7z}^{2}  +  { - x}^{2} -  {y}^{2}   -  {2z}^{2}

 {3x}^{2}  +  {3x}^{2}  { - x}^{2}  { - 7y}^{2}  { - y}^{2}  { - y}^{2}  { + z}^{2}  +  {7z}^{2}  -  {2z}^{2}

 {5x}^{2}  -  {9y}^{2}  +  {6z}^{2}

 {5x}^{2}  -  {9y}^{2}  +  {6z}^{2}  - ( {x}^{2}  -  {5y}^{2}  +  {2z}^{2} )

 {5x}^{2}  -  {9y}^{2}  +  {6z}^{2}  -  {x}^{2}  +  {5y}^{2}  -  {2z}^{2}

 {5x}^{2}  -  {x}^{2}  -  {9y}^{2}  +  {5y}^{2}  +  {6z}^{2}  -  {2z}^{2}

 {4x}^{2}  -  {4y}^{2}  +   {4z}^{2}

4( {x}^{2}  -  {y}^{2}  +  {z}^{2} )

HOPE IT HELPS YOU❤❤


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